Base | Representation |
---|---|
bin | 110000001101011111011… |
… | …001011111001100110011 |
3 | 102201201111002012011221111 |
4 | 300031133121133030303 |
5 | 413240031144132011 |
6 | 11013551442534151 |
7 | 461233505632111 |
oct | 60153731371463 |
9 | 12651432164844 |
10 | 3313020302131 |
11 | 1068053654751 |
12 | 456103967357 |
13 | 1b0554cbb2a7 |
14 | b64cb36aab1 |
15 | 5b2a5015121 |
hex | 3035f65f333 |
3313020302131 has 2 divisors, whose sum is σ = 3313020302132. Its totient is φ = 3313020302130.
The previous prime is 3313020302063. The next prime is 3313020302147. The reversal of 3313020302131 is 1312030203133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3313020302131 - 237 = 3175581348659 is a prime.
It is a super-3 number, since 3×33130203021313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3313020302171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656510151065 + 1656510151066.
It is an arithmetic number, because the mean of its divisors is an integer number (1656510151066).
Almost surely, 23313020302131 is an apocalyptic number.
3313020302131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3313020302131 is an equidigital number, since it uses as much as digits as its factorization.
3313020302131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 3313020302131 its reverse (1312030203133), we get a palindrome (4625050505264).
The spelling of 3313020302131 in words is "three trillion, three hundred thirteen billion, twenty million, three hundred two thousand, one hundred thirty-one".
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