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331302201130993 is a prime number
BaseRepresentation
bin100101101010100010100111…
…0000000101111111111110001
31121110001011220000210211122111
41023111011032000233333301
5321411023401442142433
63132342044033005321
7126532536251150341
oct11325051600577761
91543034800724574
10331302201130993
1196621524564a94
12311a87049b3841
13112b2881977871
145bb517d820d21
152847de58eedcd
hex12d514e02fff1

331302201130993 has 2 divisors, whose sum is σ = 331302201130994. Its totient is φ = 331302201130992.

The previous prime is 331302201130961. The next prime is 331302201131017. The reversal of 331302201130993 is 399031102203133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 316024288893184 + 15277912237809 = 17777072^2 + 3908697^2 .

It is an emirp because it is prime and its reverse (399031102203133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 331302201130993 - 25 = 331302201130961 is a prime.

It is a super-2 number, since 2×3313022011309932 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (331302201130793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165651100565496 + 165651100565497.

It is an arithmetic number, because the mean of its divisors is an integer number (165651100565497).

Almost surely, 2331302201130993 is an apocalyptic number.

It is an amenable number.

331302201130993 is a deficient number, since it is larger than the sum of its proper divisors (1).

331302201130993 is an equidigital number, since it uses as much as digits as its factorization.

331302201130993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 40.

The spelling of 331302201130993 in words is "three hundred thirty-one trillion, three hundred two billion, two hundred one million, one hundred thirty thousand, nine hundred ninety-three".