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33131012113 = 73453849481
BaseRepresentation
bin11110110110110000…
…110010000000010001
310011111221211210112201
4132312300302000101
51020323014341423
623115320323201
72252005646023
oct366660620021
9104457753481
1033131012113
1113061657851
126507613501
13317cc5a9a4
1418641d6013
15cdd94b2ad
hex7b6c32011

33131012113 has 4 divisors (see below), whose sum is σ = 33584861668. Its totient is φ = 32677162560.

The previous prime is 33131012111. The next prime is 33131012149. The reversal of 33131012113 is 31121013133.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27533428624 + 5597583489 = 165932^2 + 74817^2 .

It is a cyclic number.

It is not a de Polignac number, because 33131012113 - 21 = 33131012111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33131012111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226924668 + ... + 226924813.

It is an arithmetic number, because the mean of its divisors is an integer number (8396215417).

Almost surely, 233131012113 is an apocalyptic number.

It is an amenable number.

33131012113 is a deficient number, since it is larger than the sum of its proper divisors (453849555).

33131012113 is an equidigital number, since it uses as much as digits as its factorization.

33131012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 453849554.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 33131012113 its reverse (31121013133), we get a palindrome (64252025246).

The spelling of 33131012113 in words is "thirty-three billion, one hundred thirty-one million, twelve thousand, one hundred thirteen".

Divisors: 1 73 453849481 33131012113