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3313110322113 = 31104370107371
BaseRepresentation
bin110000001101100100110…
…000111000101111000001
3102201201201100120200010220
4300031210300320233001
5413240222220301423
611014004420213253
7461235651040044
oct60154460705701
912651640520126
103313110322113
11106809a44a029
12456129b3a229
131b056a849357
14b64d92c0c5b
155b2acd979e3
hex30364c38bc1

3313110322113 has 4 divisors (see below), whose sum is σ = 4417480429488. Its totient is φ = 2208740214740.

The previous prime is 3313110322099. The next prime is 3313110322121. The reversal of 3313110322113 is 3112230113133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3313110322113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3313110322133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 552185053683 + ... + 552185053688.

It is an arithmetic number, because the mean of its divisors is an integer number (1104370107372).

Almost surely, 23313110322113 is an apocalyptic number.

It is an amenable number.

3313110322113 is a deficient number, since it is larger than the sum of its proper divisors (1104370107375).

3313110322113 is a wasteful number, since it uses less digits than its factorization.

3313110322113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1104370107374.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 3313110322113 its reverse (3112230113133), we get a palindrome (6425340435246).

The spelling of 3313110322113 in words is "three trillion, three hundred thirteen billion, one hundred ten million, three hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 1104370107371 3313110322113