Base | Representation |
---|---|
bin | 1111000100100000100010… |
… | …00101111110001011011011 |
3 | 11100100011210022102111112022 |
4 | 13202100101011332023123 |
5 | 13320432220113342021 |
6 | 154252231150005055 |
7 | 6660206253562604 |
oct | 742202105761333 |
9 | 140304708374468 |
10 | 33140254434011 |
11 | a617780732a0a |
12 | 38729781a678b |
13 | 1565160466aba |
14 | 827dd55c2dab |
15 | 3c70c274c1ab |
hex | 1e241117e2db |
33140254434011 has 16 divisors (see below), whose sum is σ = 33447928631040. Its totient is φ = 32833419833760.
The previous prime is 33140254433927. The next prime is 33140254434017. The reversal of 33140254434011 is 11043445204133.
It is a cyclic number.
It is not a de Polignac number, because 33140254434011 - 230 = 33139180692187 is a prime.
It is a super-3 number, since 3×331402544340113 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33140254434017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1241985476 + ... + 1242012158.
It is an arithmetic number, because the mean of its divisors is an integer number (2090495539440).
Almost surely, 233140254434011 is an apocalyptic number.
33140254434011 is a deficient number, since it is larger than the sum of its proper divisors (307674197029).
33140254434011 is a wasteful number, since it uses less digits than its factorization.
33140254434011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41986.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 33140254434011 its reverse (11043445204133), we get a palindrome (44183699638144).
The spelling of 33140254434011 in words is "thirty-three trillion, one hundred forty billion, two hundred fifty-four million, four hundred thirty-four thousand, eleven".
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