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33140254434017 is a prime number
BaseRepresentation
bin1111000100100000100010…
…00101111110001011100001
311100100011210022102111112112
413202100101011332023201
513320432220113342032
6154252231150005105
76660206253562613
oct742202105761341
9140304708374475
1033140254434017
11a617780732a15
1238729781a6795
131565160466ac3
14827dd55c2db3
153c70c274c1b2
hex1e241117e2e1

33140254434017 has 2 divisors, whose sum is σ = 33140254434018. Its totient is φ = 33140254434016.

The previous prime is 33140254433927. The next prime is 33140254434031. The reversal of 33140254434017 is 71043445204133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26101840128016 + 7038414306001 = 5108996^2 + 2653001^2 .

It is a cyclic number.

It is not a de Polignac number, because 33140254434017 - 212 = 33140254429921 is a prime.

It is not a weakly prime, because it can be changed into another prime (33140254434097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16570127217008 + 16570127217009.

It is an arithmetic number, because the mean of its divisors is an integer number (16570127217009).

Almost surely, 233140254434017 is an apocalyptic number.

It is an amenable number.

33140254434017 is a deficient number, since it is larger than the sum of its proper divisors (1).

33140254434017 is an equidigital number, since it uses as much as digits as its factorization.

33140254434017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 41.

The spelling of 33140254434017 in words is "thirty-three trillion, one hundred forty billion, two hundred fifty-four million, four hundred thirty-four thousand, seventeen".