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331412262214081 is a prime number
BaseRepresentation
bin100101101011010101110111…
…0001010011101100111000001
31121110102200222101011011021011
41023112223232022131213001
5321414324303111322311
63132504405204000521
7126543513544005526
oct11326535612354701
91543380871134234
10331412262214081
1196664173135794
1231205b00090141
13112c0071a106b9
145bba620b8514d
15284abd8061321
hex12d6aee29d9c1

331412262214081 has 2 divisors, whose sum is σ = 331412262214082. Its totient is φ = 331412262214080.

The previous prime is 331412262214067. The next prime is 331412262214129. The reversal of 331412262214081 is 180412262214133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 330427323075600 + 984939138481 = 18177660^2 + 992441^2 .

It is a cyclic number.

It is not a de Polignac number, because 331412262214081 - 215 = 331412262181313 is a prime.

It is a super-2 number, since 2×3314122622140812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (331412262214001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165706131107040 + 165706131107041.

It is an arithmetic number, because the mean of its divisors is an integer number (165706131107041).

Almost surely, 2331412262214081 is an apocalyptic number.

It is an amenable number.

331412262214081 is a deficient number, since it is larger than the sum of its proper divisors (1).

331412262214081 is an equidigital number, since it uses as much as digits as its factorization.

331412262214081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 40.

The spelling of 331412262214081 in words is "three hundred thirty-one trillion, four hundred twelve billion, two hundred sixty-two million, two hundred fourteen thousand, eighty-one".