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3314132023481 is a prime number
BaseRepresentation
bin110000001110100001101…
…010010111100010111001
3102201211100120002110221022
4300032201222113202321
5413244320244222411
611014254034552225
7461303165254166
oct60164152274271
912654316073838
103314132023481
111068574145424
12456374138675
131b06a1414186
14b6594c7b06d
155b31c913edb
hex303a1a978b9

3314132023481 has 2 divisors, whose sum is σ = 3314132023482. Its totient is φ = 3314132023480.

The previous prime is 3314132023439. The next prime is 3314132023493. The reversal of 3314132023481 is 1843202314133.

3314132023481 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2098094310400 + 1216037713081 = 1448480^2 + 1102741^2 .

It is a cyclic number.

It is not a de Polignac number, because 3314132023481 - 214 = 3314132007097 is a prime.

It is a super-2 number, since 2×33141320234812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3314132023381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657066011740 + 1657066011741.

It is an arithmetic number, because the mean of its divisors is an integer number (1657066011741).

Almost surely, 23314132023481 is an apocalyptic number.

It is an amenable number.

3314132023481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3314132023481 is an equidigital number, since it uses as much as digits as its factorization.

3314132023481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 3314132023481 in words is "three trillion, three hundred fourteen billion, one hundred thirty-two million, twenty-three thousand, four hundred eighty-one".