Base | Representation |
---|---|
bin | 110000001110110010011… |
… | …011000001100111001001 |
3 | 102201212002011012110000122 |
4 | 300032302123001213021 |
5 | 413300404240323103 |
6 | 11014342001513025 |
7 | 461313151324106 |
oct | 60166233014711 |
9 | 12655064173018 |
10 | 3314413214153 |
11 | 10686a8942108 |
12 | 456432342775 |
13 | 1b07177577a2 |
14 | b65c0355aad |
15 | 5b337459b38 |
hex | 303b26c19c9 |
3314413214153 has 2 divisors, whose sum is σ = 3314413214154. Its totient is φ = 3314413214152.
The previous prime is 3314413214051. The next prime is 3314413214171. The reversal of 3314413214153 is 3514123144133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2742193585849 + 572219628304 = 1655957^2 + 756452^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3314413214153 is a prime.
It is not a weakly prime, because it can be changed into another prime (3314413214753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657206607076 + 1657206607077.
It is an arithmetic number, because the mean of its divisors is an integer number (1657206607077).
Almost surely, 23314413214153 is an apocalyptic number.
It is an amenable number.
3314413214153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314413214153 is an equidigital number, since it uses as much as digits as its factorization.
3314413214153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51840, while the sum is 35.
Adding to 3314413214153 its reverse (3514123144133), we get a palindrome (6828536358286).
The spelling of 3314413214153 in words is "three trillion, three hundred fourteen billion, four hundred thirteen million, two hundred fourteen thousand, one hundred fifty-three".
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