Base | Representation |
---|---|
bin | 1001101001011001011… |
… | …01100011010001010001 |
3 | 1011200120012101201220021 |
4 | 10310230231203101101 |
5 | 20412313412321431 |
6 | 412134414143441 |
7 | 32642644533214 |
oct | 4645455432121 |
9 | 1150505351807 |
10 | 331462620241 |
11 | 11863300a595 |
12 | 542a61b1b81 |
13 | 25345228c6c |
14 | 1208591d77b |
15 | 894e8ebb11 |
hex | 4d2cb63451 |
331462620241 has 2 divisors, whose sum is σ = 331462620242. Its totient is φ = 331462620240.
The previous prime is 331462620127. The next prime is 331462620253. The reversal of 331462620241 is 142026264133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 329567846400 + 1894773841 = 574080^2 + 43529^2 .
It is a cyclic number.
It is not a de Polignac number, because 331462620241 - 213 = 331462612049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 331462620197 and 331462620206.
It is not a weakly prime, because it can be changed into another prime (331462600241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165731310120 + 165731310121.
It is an arithmetic number, because the mean of its divisors is an integer number (165731310121).
Almost surely, 2331462620241 is an apocalyptic number.
It is an amenable number.
331462620241 is a deficient number, since it is larger than the sum of its proper divisors (1).
331462620241 is an equidigital number, since it uses as much as digits as its factorization.
331462620241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 331462620241 its reverse (142026264133), we get a palindrome (473488884374).
The spelling of 331462620241 in words is "three hundred thirty-one billion, four hundred sixty-two million, six hundred twenty thousand, two hundred forty-one".
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