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33149113 is a prime number
BaseRepresentation
bin111111001110…
…1000010111001
32022101011000221
41332131002321
531441232423
63142300041
7551522434
oct176350271
968334027
1033149113
1117791468
12b127621
136b3847a
14458c81b
152d9be5d
hex1f9d0b9

33149113 has 2 divisors, whose sum is σ = 33149114. Its totient is φ = 33149112.

The previous prime is 33149107. The next prime is 33149131. The reversal of 33149113 is 31194133.

Together with next prime (33149131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33028009 + 121104 = 5747^2 + 348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-33149113 is a prime.

It is not a weakly prime, because it can be changed into another prime (33149153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16574556 + 16574557.

It is an arithmetic number, because the mean of its divisors is an integer number (16574557).

Almost surely, 233149113 is an apocalyptic number.

It is an amenable number.

33149113 is a deficient number, since it is larger than the sum of its proper divisors (1).

33149113 is an equidigital number, since it uses as much as digits as its factorization.

33149113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 25.

The square root of 33149113 is about 5757.5266391047. The cubic root of 33149113 is about 321.2358233838.

The spelling of 33149113 in words is "thirty-three million, one hundred forty-nine thousand, one hundred thirteen".