Base | Representation |
---|---|
bin | 110000001111011101110… |
… | …000111000001101101001 |
3 | 102201220221211110102212121 |
4 | 300033131300320031221 |
5 | 413303401413104423 |
6 | 11014542055111241 |
7 | 461340161100655 |
oct | 60173560701551 |
9 | 12656854412777 |
10 | 3315140363113 |
11 | 1068a41344967 |
12 | 4565b5972521 |
13 | 1b08022b1247 |
14 | b664cb59a65 |
15 | 5b37b1e145d |
hex | 303ddc38369 |
3315140363113 has 2 divisors, whose sum is σ = 3315140363114. Its totient is φ = 3315140363112.
The previous prime is 3315140363099. The next prime is 3315140363149. The reversal of 3315140363113 is 3113630415133.
3315140363113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3314467842624 + 672520489 = 1820568^2 + 25933^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3315140363113 is a prime.
It is not a weakly prime, because it can be changed into another prime (3315140363153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657570181556 + 1657570181557.
It is an arithmetic number, because the mean of its divisors is an integer number (1657570181557).
Almost surely, 23315140363113 is an apocalyptic number.
It is an amenable number.
3315140363113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3315140363113 is an equidigital number, since it uses as much as digits as its factorization.
3315140363113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29160, while the sum is 34.
Adding to 3315140363113 its reverse (3113630415133), we get a palindrome (6428770778246).
The spelling of 3315140363113 in words is "three trillion, three hundred fifteen billion, one hundred forty million, three hundred sixty-three thousand, one hundred thirteen".
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