Base | Representation |
---|---|
bin | 110000001111101101001… |
… | …111110100101000101001 |
3 | 102201221121221021010101111 |
4 | 300033231033310220221 |
5 | 413304414413230121 |
6 | 11015023534550321 |
7 | 461346464104024 |
oct | 60175517645051 |
9 | 12657557233344 |
10 | 3315400133161 |
11 | 1069064a40a56 |
12 | 4566689683a1 |
13 | 1b084406492c |
14 | b667545a1bb |
15 | 5b393e052e1 |
hex | 303ed3f4a29 |
3315400133161 has 2 divisors, whose sum is σ = 3315400133162. Its totient is φ = 3315400133160.
The previous prime is 3315400133117. The next prime is 3315400133173. The reversal of 3315400133161 is 1613310045133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2529817491600 + 785582641561 = 1590540^2 + 886331^2 .
It is a cyclic number.
It is not a de Polignac number, because 3315400133161 - 225 = 3315366578729 is a prime.
It is not a weakly prime, because it can be changed into another prime (3315400133191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657700066580 + 1657700066581.
It is an arithmetic number, because the mean of its divisors is an integer number (1657700066581).
Almost surely, 23315400133161 is an apocalyptic number.
It is an amenable number.
3315400133161 is a deficient number, since it is larger than the sum of its proper divisors (1).
3315400133161 is an equidigital number, since it uses as much as digits as its factorization.
3315400133161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 3315400133161 its reverse (1613310045133), we get a palindrome (4928710178294).
The spelling of 3315400133161 in words is "three trillion, three hundred fifteen billion, four hundred million, one hundred thirty-three thousand, one hundred sixty-one".
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