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3316641440113 = 30111101508283
BaseRepresentation
bin110000010000110111001…
…111000010000101110001
3102202001211110000001102001
4300100313033002011301
5413314440202040423
611015351040254001
7461422316042521
oct60206717020561
912661743001361
103316641440113
1110696416a0271
12456954611301
131b09b128c7a1
14b675225d681
155b417d9ecad
hex304373c2171

3316641440113 has 4 divisors (see below), whose sum is σ = 3317742951408. Its totient is φ = 3315539928820.

The previous prime is 3316641440107. The next prime is 3316641440141. The reversal of 3316641440113 is 3110441466133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3316641440113 - 213 = 3316641431921 is a prime.

It is a super-2 number, since 2×33166414401132 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3316641440153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550751131 + ... + 550757152.

It is an arithmetic number, because the mean of its divisors is an integer number (829435737852).

Almost surely, 23316641440113 is an apocalyptic number.

It is an amenable number.

3316641440113 is a deficient number, since it is larger than the sum of its proper divisors (1101511295).

3316641440113 is a wasteful number, since it uses less digits than its factorization.

3316641440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1101511294.

The product of its (nonzero) digits is 62208, while the sum is 37.

The spelling of 3316641440113 in words is "three trillion, three hundred sixteen billion, six hundred forty-one million, four hundred forty thousand, one hundred thirteen".

Divisors: 1 3011 1101508283 3316641440113