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33199141649 is a prime number
BaseRepresentation
bin11110111010110100…
…101011001100010001
310011200201001010200212
4132322310223030101
51020442440013044
623130152453505
72253464022302
oct367264531421
9104621033625
1033199141649
1113097060553
1265263aa295
1331910c301b
14186d28c7a9
15ce4907a9e
hex7bad2b311

33199141649 has 2 divisors, whose sum is σ = 33199141650. Its totient is φ = 33199141648.

The previous prime is 33199141639. The next prime is 33199141727. The reversal of 33199141649 is 94614199133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27271219600 + 5927922049 = 165140^2 + 76993^2 .

It is an emirp because it is prime and its reverse (94614199133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33199141649 - 212 = 33199137553 is a prime.

It is a super-2 number, since 2×331991416492 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33199141597 and 33199141606.

It is not a weakly prime, because it can be changed into another prime (33199141639) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16599570824 + 16599570825.

It is an arithmetic number, because the mean of its divisors is an integer number (16599570825).

Almost surely, 233199141649 is an apocalyptic number.

It is an amenable number.

33199141649 is a deficient number, since it is larger than the sum of its proper divisors (1).

33199141649 is an equidigital number, since it uses as much as digits as its factorization.

33199141649 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 629856, while the sum is 50.

The spelling of 33199141649 in words is "thirty-three billion, one hundred ninety-nine million, one hundred forty-one thousand, six hundred forty-nine".