Base | Representation |
---|---|
bin | 110000010100000001011… |
… | …100101111011001100001 |
3 | 102202101120212202112110211 |
4 | 300110001130233121201 |
5 | 413343412202444301 |
6 | 11021111431254121 |
7 | 461602352431606 |
oct | 60240134573141 |
9 | 12671525675424 |
10 | 3320034031201 |
11 | 1070022726158 |
12 | 45754081a341 |
13 | 1b11020c0234 |
14 | b6994a5c6ad |
15 | 5b565b42051 |
hex | 3050172f661 |
3320034031201 has 2 divisors, whose sum is σ = 3320034031202. Its totient is φ = 3320034031200.
The previous prime is 3320034031187. The next prime is 3320034031231. The reversal of 3320034031201 is 1021304300233.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2836799118400 + 483234912801 = 1684280^2 + 695151^2 .
It is a cyclic number.
It is not a de Polignac number, because 3320034031201 - 27 = 3320034031073 is a prime.
It is a super-2 number, since 2×33200340312012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3320034031231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660017015600 + 1660017015601.
It is an arithmetic number, because the mean of its divisors is an integer number (1660017015601).
Almost surely, 23320034031201 is an apocalyptic number.
It is an amenable number.
3320034031201 is a deficient number, since it is larger than the sum of its proper divisors (1).
3320034031201 is an equidigital number, since it uses as much as digits as its factorization.
3320034031201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3320034031201 its reverse (1021304300233), we get a palindrome (4341338331434).
The spelling of 3320034031201 in words is "three trillion, three hundred twenty billion, thirty-four million, thirty-one thousand, two hundred one".
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