Base | Representation |
---|---|
bin | 100101101111101101101010… |
… | …0010000110110001010011011 |
3 | 1121112120010220101220211001122 |
4 | 1023133123110100312022123 |
5 | 322004200334003220324 |
6 | 3134044420110035455 |
7 | 126635104462201121 |
oct | 11337332420661233 |
9 | 1545503811824048 |
10 | 332013123101339 |
11 | 96875a7a476659 |
12 | 312a244b1a8b8b |
13 | 1133491ab1b844 |
14 | 5bdb7414c3911 |
15 | 285b653781a5e |
hex | 12df6d443629b |
332013123101339 has 2 divisors, whose sum is σ = 332013123101340. Its totient is φ = 332013123101338.
The previous prime is 332013123101269. The next prime is 332013123101357. The reversal of 332013123101339 is 933101321310233.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-332013123101339 is a prime.
It is a super-2 number, since 2×3320131231013392 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332013123101299 and 332013123101308.
It is not a weakly prime, because it can be changed into another prime (332013123101039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166006561550669 + 166006561550670.
It is an arithmetic number, because the mean of its divisors is an integer number (166006561550670).
Almost surely, 2332013123101339 is an apocalyptic number.
332013123101339 is a deficient number, since it is larger than the sum of its proper divisors (1).
332013123101339 is an equidigital number, since it uses as much as digits as its factorization.
332013123101339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 35.
The spelling of 332013123101339 in words is "three hundred thirty-two trillion, thirteen billion, one hundred twenty-three million, one hundred one thousand, three hundred thirty-nine".
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