3320133433 has 2 divisors, whose sum is σ = 3320133434. Its totient is φ = 3320133432.

The previous prime is 3320133407. The next prime is 3320133461. The reversal of 3320133433 is 3343310233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2995701289 + 324432144 = 54733^2 + 18012^2 .

It is an emirp because it is prime and its reverse (3343310233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3320133433 - 2²⁵ = 3286579001 is a prime.

It is a super-2 number, since 2×3320133433² = 22046572025848730978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3320133398 and 3320133407.

It is not a weakly prime, because it can be changed into another prime (3320143433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660066716 + 1660066717.

It is an arithmetic number, because the mean of its divisors is an integer number (1660066717).

Almost surely, 2^3320133433 is an apocalyptic number.

It is an amenable number.

3320133433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3320133433 is an equidigital number, since it uses as much as digits as its factorization.

3320133433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 25.

The square root of 3320133433 is about 57620.5990336789. The cubic root of 3320133433 is about 1491.8271704837.

Adding to 3320133433 its reverse (3343310233), we get a palindrome (6663443666).

The spelling of 3320133433 in words is "three billion, three hundred twenty million, one hundred thirty-three thousand, four hundred thirty-three".