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33204034113 = 3101311352361
BaseRepresentation
bin11110111011000111…
…010101101001000001
310011201001020200220020
4132323013111221001
51021000213042423
623130445404053
72253553430115
oct367307255101
9104631220806
1033204034113
11130998a2308
126527b69629
133192116b83
14186dba3745
15ce50724e3
hex7bb1d5a41

33204034113 has 16 divisors (see below), whose sum is σ = 44854273152. Its totient is φ = 21846320000.

The previous prime is 33204034093. The next prime is 33204034147. The reversal of 33204034113 is 31143040233.

It is a cyclic number.

It is not a de Polignac number, because 33204034113 - 214 = 33204017729 is a prime.

It is a super-2 number, since 2×332040341132 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (33204036113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81948 + ... + 270413.

It is an arithmetic number, because the mean of its divisors is an integer number (2803392072).

Almost surely, 233204034113 is an apocalyptic number.

It is an amenable number.

33204034113 is a deficient number, since it is larger than the sum of its proper divisors (11650239039).

33204034113 is a wasteful number, since it uses less digits than its factorization.

33204034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 352776.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 33204034113 its reverse (31143040233), we get a palindrome (64347074346).

The spelling of 33204034113 in words is "thirty-three billion, two hundred four million, thirty-four thousand, one hundred thirteen".

Divisors: 1 3 101 303 311 933 31411 94233 352361 1057083 35588461 106765383 109584271 328752813 11068011371 33204034113