Base | Representation |
---|---|
bin | 110000010100111011001… |
… | …001010011000101011011 |
3 | 102202111002100012002220021 |
4 | 300110323021103011123 |
5 | 413402403003404034 |
6 | 11021351450411311 |
7 | 461635345230205 |
oct | 60247311230533 |
9 | 12674070162807 |
10 | 3321002013019 |
11 | 107047a070229 |
12 | 457770a30b37 |
13 | 1b12277c9942 |
14 | b6a47433775 |
15 | 5b5c0aeb6b4 |
hex | 3053b25315b |
3321002013019 has 2 divisors, whose sum is σ = 3321002013020. Its totient is φ = 3321002013018.
The previous prime is 3321002013001. The next prime is 3321002013023. The reversal of 3321002013019 is 9103102001233.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3321002013019 - 217 = 3321001881947 is a prime.
It is a super-2 number, since 2×33210020130192 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3321002012984 and 3321002013002.
It is not a weakly prime, because it can be changed into another prime (3321002013089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660501006509 + 1660501006510.
It is an arithmetic number, because the mean of its divisors is an integer number (1660501006510).
Almost surely, 23321002013019 is an apocalyptic number.
3321002013019 is a deficient number, since it is larger than the sum of its proper divisors (1).
3321002013019 is an equidigital number, since it uses as much as digits as its factorization.
3321002013019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 3321002013019 in words is "three trillion, three hundred twenty-one billion, two million, thirteen thousand, nineteen".
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