Base | Representation |
---|---|
bin | 1001101010100101101… |
… | …00101001000011000001 |
3 | 1011202012202112021001001 |
4 | 10311102310221003001 |
5 | 20420121103404441 |
6 | 412322054412001 |
7 | 32664540351334 |
oct | 4652264510301 |
9 | 1152182467031 |
10 | 332102013121 |
11 | 118930a2395a |
12 | 54444361001 |
13 | 25417837c48 |
14 | 121067dc61b |
15 | 898aaeb731 |
hex | 4d52d290c1 |
332102013121 has 2 divisors, whose sum is σ = 332102013122. Its totient is φ = 332102013120.
The previous prime is 332102013097. The next prime is 332102013143. The reversal of 332102013121 is 121310201233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 268001900721 + 64100112400 = 517689^2 + 253180^2 .
It is a cyclic number.
It is not a de Polignac number, because 332102013121 - 29 = 332102012609 is a prime.
It is a super-3 number, since 3×3321020131213 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (332102013161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166051006560 + 166051006561.
It is an arithmetic number, because the mean of its divisors is an integer number (166051006561).
Almost surely, 2332102013121 is an apocalyptic number.
It is an amenable number.
332102013121 is a deficient number, since it is larger than the sum of its proper divisors (1).
332102013121 is an equidigital number, since it uses as much as digits as its factorization.
332102013121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 332102013121 its reverse (121310201233), we get a palindrome (453412214354).
The spelling of 332102013121 in words is "three hundred thirty-two billion, one hundred two million, thirteen thousand, one hundred twenty-one".
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