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3321021109993 is a prime number
BaseRepresentation
bin110000010100111100010…
…010001001011011101001
3102202111010200010100000121
4300110330102021123221
5413402422401004433
611021353412003241
7461635666445416
oct60247422113351
912674120110017
103321021109993
111070489924054
12457777300521
131b122b755022
14b6a49ba510d
155b5c261ec2d
hex3053c4896e9

3321021109993 has 2 divisors, whose sum is σ = 3321021109994. Its totient is φ = 3321021109992.

The previous prime is 3321021109949. The next prime is 3321021110059. The reversal of 3321021109993 is 3999011201233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2702302001424 + 618719108569 = 1643868^2 + 786587^2 .

It is an emirp because it is prime and its reverse (3999011201233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3321021109993 - 29 = 3321021109481 is a prime.

It is a super-2 number, since 2×33210211099932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3321021109093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660510554996 + 1660510554997.

It is an arithmetic number, because the mean of its divisors is an integer number (1660510554997).

Almost surely, 23321021109993 is an apocalyptic number.

It is an amenable number.

3321021109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3321021109993 is an equidigital number, since it uses as much as digits as its factorization.

3321021109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78732, while the sum is 43.

The spelling of 3321021109993 in words is "three trillion, three hundred twenty-one billion, twenty-one million, one hundred nine thousand, nine hundred ninety-three".