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3321124000234 = 21660562000117
BaseRepresentation
bin110000010101000010011…
…010101001000111101010
3102202111101211201200220021
4300111002122221013222
5413403130221001414
611021411525151054
7461641356136105
oct60250232510752
912674354650807
103321124000234
111070531a0a007
124577a585b48a
131b1246b6b221
14b6a5970973c
155b5cb695c24
hex305426a91ea

3321124000234 has 4 divisors (see below), whose sum is σ = 4981686000354. Its totient is φ = 1660562000116.

The previous prime is 3321124000231. The next prime is 3321124000297. The reversal of 3321124000234 is 4320004211233.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3172477511025 + 148646489209 = 1781145^2 + 385547^2 .

It is a super-2 number, since 2×33211240002342 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3321124000199 and 3321124000208.

It is not an unprimeable number, because it can be changed into a prime (3321124000231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 830281000057 + ... + 830281000060.

Almost surely, 23321124000234 is an apocalyptic number.

3321124000234 is a deficient number, since it is larger than the sum of its proper divisors (1660562000120).

3321124000234 is a wasteful number, since it uses less digits than its factorization.

3321124000234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1660562000119.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 3321124000234 its reverse (4320004211233), we get a palindrome (7641128211467).

The spelling of 3321124000234 in words is "three trillion, three hundred twenty-one billion, one hundred twenty-four million, two hundred thirty-four", and thus it is an aban number.

Divisors: 1 2 1660562000117 3321124000234