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3321140411257 is a prime number
BaseRepresentation
bin110000010101000011011…
…001001111101101111001
3102202111102222121110120221
4300111003121033231321
5413403143421130012
611021413313020041
7461641645466464
oct60250331175571
912674388543527
103321140411257
1110705401a8939
124577ab254621
131b124a395ba6
14b6a5b97c2db
155b5ccd38507
hex3054364fb79

3321140411257 has 2 divisors, whose sum is σ = 3321140411258. Its totient is φ = 3321140411256.

The previous prime is 3321140411219. The next prime is 3321140411279. The reversal of 3321140411257 is 7521140411233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2209610898576 + 1111529512681 = 1486476^2 + 1054291^2 .

It is an emirp because it is prime and its reverse (7521140411233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3321140411257 - 215 = 3321140378489 is a prime.

It is a super-2 number, since 2×33211404112572 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3321140411557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660570205628 + 1660570205629.

It is an arithmetic number, because the mean of its divisors is an integer number (1660570205629).

Almost surely, 23321140411257 is an apocalyptic number.

It is an amenable number.

3321140411257 is a deficient number, since it is larger than the sum of its proper divisors (1).

3321140411257 is an equidigital number, since it uses as much as digits as its factorization.

3321140411257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 3321140411257 in words is "three trillion, three hundred twenty-one billion, one hundred forty million, four hundred eleven thousand, two hundred fifty-seven".