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332120342113 = 7311530508489
BaseRepresentation
bin1001101010100111110…
…10100011111001100001
31011202021001000110200121
410311103322203321201
520420140301421423
6412323551320241
732665152220540
oct4652372437141
91152231013617
10332120342113
1111894030278a
125444a520081
132541b5848c1
1412109010157
15898c51c45d
hex4d53ea3e61

332120342113 has 8 divisors (see below), whose sum is σ = 391810173440. Its totient is φ = 275491527840.

The previous prime is 332120342101. The next prime is 332120342207. The reversal of 332120342113 is 311243021233.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 332120342113 - 237 = 194681388641 is a prime.

It is a super-2 number, since 2×3321203421132 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (332120342413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 765254028 + ... + 765254461.

It is an arithmetic number, because the mean of its divisors is an integer number (48976271680).

Almost surely, 2332120342113 is an apocalyptic number.

It is an amenable number.

332120342113 is a deficient number, since it is larger than the sum of its proper divisors (59689831327).

332120342113 is a wasteful number, since it uses less digits than its factorization.

332120342113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1530508527.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 332120342113 its reverse (311243021233), we get a palindrome (643363363346).

The spelling of 332120342113 in words is "three hundred thirty-two billion, one hundred twenty million, three hundred forty-two thousand, one hundred thirteen".

Divisors: 1 7 31 217 1530508489 10713559423 47445763159 332120342113