Base | Representation |
---|---|
bin | 110000010101000111101… |
… | …011100011100110000011 |
3 | 102202111121222220211000120 |
4 | 300111013223203212003 |
5 | 413403320323221011 |
6 | 11021424402151323 |
7 | 461643510633366 |
oct | 60250753434603 |
9 | 12674558824016 |
10 | 3321212320131 |
11 | 1070577853062 |
12 | 45780b352543 |
13 | 1b125c252514 |
14 | b6a6733a0dd |
15 | 5b5d42dea06 |
hex | 30547ae3983 |
3321212320131 has 8 divisors (see below), whose sum is σ = 4531266421440. Its totient is φ = 2162649882792.
The previous prime is 3321212320117. The next prime is 3321212320159. The reversal of 3321212320131 is 1310232121233.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3321212320131 - 27 = 3321212320003 is a prime.
It is a super-2 number, since 2×33212123201312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3321212320631) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12872915841 + ... + 12872916098.
It is an arithmetic number, because the mean of its divisors is an integer number (566408302680).
Almost surely, 23321212320131 is an apocalyptic number.
3321212320131 is a deficient number, since it is larger than the sum of its proper divisors (1210054101309).
3321212320131 is a wasteful number, since it uses less digits than its factorization.
3321212320131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25745831985.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 3321212320131 its reverse (1310232121233), we get a palindrome (4631444441364).
The spelling of 3321212320131 in words is "three trillion, three hundred twenty-one billion, two hundred twelve million, three hundred twenty thousand, one hundred thirty-one".
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