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332122201310041 = 1266132623128757
BaseRepresentation
bin100101110000100000011100…
…1110101001100001101011001
31121112221120110020210221111021
41023201000321311030031121
5322012442232013410131
63134210455530402441
7126646015521523312
oct11341007165141531
91545846406727437
10332122201310041
119690826426027a
12312bb611290421
1311341cb23624bc
145c02b2c0b7609
15285e3d9995e11
hex12e1039d4c359

332122201310041 has 4 divisors (see below), whose sum is σ = 332124824565412. Its totient is φ = 332119578054672.

The previous prime is 332122201309979. The next prime is 332122201310077. The reversal of 332122201310041 is 140013102221233.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 193221008956816 + 138901192353225 = 13900396^2 + 11785635^2 .

It is a cyclic number.

It is not a de Polignac number, because 332122201310041 - 211 = 332122201307993 is a prime.

It is a super-2 number, since 2×3321222013100412 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 332122201309988 and 332122201310015.

It is not an unprimeable number, because it can be changed into a prime (332122201310741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311437766 + ... + 1311690991.

It is an arithmetic number, because the mean of its divisors is an integer number (83031206141353).

Almost surely, 2332122201310041 is an apocalyptic number.

It is an amenable number.

332122201310041 is a deficient number, since it is larger than the sum of its proper divisors (2623255371).

332122201310041 is a wasteful number, since it uses less digits than its factorization.

332122201310041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2623255370.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 332122201310041 its reverse (140013102221233), we get a palindrome (472135303531274).

The spelling of 332122201310041 in words is "three hundred thirty-two trillion, one hundred twenty-two billion, two hundred one million, three hundred ten thousand, forty-one".

Divisors: 1 126613 2623128757 332122201310041