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332132101233001 is a prime number
BaseRepresentation
bin100101110000100101000011…
…1111010011001100101101001
31121112222112000012021010201121
41023201022013322121211221
5322013123020403424001
63134215214140215241
7126646516042502416
oct11341120772314551
91545875005233647
10332132101233001
1196911484530993
123130151483a521
1311342bcc3b0094
145c033cac2910d
15285e7b8b866a1
hex12e1287e99969

332132101233001 has 2 divisors, whose sum is σ = 332132101233002. Its totient is φ = 332132101233000.

The previous prime is 332132101232989. The next prime is 332132101233011. The reversal of 332132101233001 is 100332101231233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 256190915581225 + 75941185651776 = 16005965^2 + 8714424^2 .

It is a cyclic number.

It is not a de Polignac number, because 332132101233001 - 211 = 332132101230953 is a prime.

It is a super-2 number, since 2×3321321012330012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (332132101233011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166066050616500 + 166066050616501.

It is an arithmetic number, because the mean of its divisors is an integer number (166066050616501).

Almost surely, 2332132101233001 is an apocalyptic number.

It is an amenable number.

332132101233001 is a deficient number, since it is larger than the sum of its proper divisors (1).

332132101233001 is an equidigital number, since it uses as much as digits as its factorization.

332132101233001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 332132101233001 its reverse (100332101231233), we get a palindrome (432464202464234).

The spelling of 332132101233001 in words is "three hundred thirty-two trillion, one hundred thirty-two billion, one hundred one million, two hundred thirty-three thousand, one".