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3321431213099 = 4127804805237
BaseRepresentation
bin110000010101010100101…
…110100100010000101011
3102202112012020210201201112
4300111110232210100223
5413404242342304344
611021502221540535
7461652106326326
oct60252456442053
912675166721645
103321431213099
11107067a36a63a
1245787071474b
131b12956c309c
14b6a884397bd
155b5e862bc9e
hex30554ba442b

3321431213099 has 4 divisors (see below), whose sum is σ = 3322236022464. Its totient is φ = 3320626403736.

The previous prime is 3321431213003. The next prime is 3321431213117. The reversal of 3321431213099 is 9903121341233.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3321431213099 is a prime.

It is a super-2 number, since 2×33214312130992 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3321431213699) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402398492 + ... + 402406745.

It is an arithmetic number, because the mean of its divisors is an integer number (830559005616).

Almost surely, 23321431213099 is an apocalyptic number.

3321431213099 is a deficient number, since it is larger than the sum of its proper divisors (804809365).

3321431213099 is an equidigital number, since it uses as much as digits as its factorization.

3321431213099 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 804809364.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 3321431213099 in words is "three trillion, three hundred twenty-one billion, four hundred thirty-one million, two hundred thirteen thousand, ninety-nine".

Divisors: 1 4127 804805237 3321431213099