Base | Representation |
---|---|
bin | 1001101010110110001… |
… | …11010000100000000011 |
3 | 1011202120110021011111221 |
4 | 10311123013100200003 |
5 | 20420412211023133 |
6 | 412343544015511 |
7 | 33001146563542 |
oct | 4653307204003 |
9 | 1152513234457 |
10 | 332241111043 |
11 | 1189a249a216 |
12 | 54482a61597 |
13 | 2543a5ba7ca |
14 | 1211b08a159 |
15 | 8997e25a2d |
hex | 4d5b1d0803 |
332241111043 has 2 divisors, whose sum is σ = 332241111044. Its totient is φ = 332241111042.
The previous prime is 332241111017. The next prime is 332241111061. The reversal of 332241111043 is 340111142233.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-332241111043 is a prime.
It is a super-2 number, since 2×3322411110432 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332241110999 and 332241111017.
It is not a weakly prime, because it can be changed into another prime (332241111143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166120555521 + 166120555522.
It is an arithmetic number, because the mean of its divisors is an integer number (166120555522).
Almost surely, 2332241111043 is an apocalyptic number.
332241111043 is a deficient number, since it is larger than the sum of its proper divisors (1).
332241111043 is an equidigital number, since it uses as much as digits as its factorization.
332241111043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 332241111043 its reverse (340111142233), we get a palindrome (672352253276).
The spelling of 332241111043 in words is "three hundred thirty-two billion, two hundred forty-one million, one hundred eleven thousand, forty-three".
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