Base | Representation |
---|---|
bin | 11110111100110101… |
… | …110101011001101001 |
3 | 10011210001202022200101 |
4 | 132330311311121221 |
5 | 1021030122000131 |
6 | 23133402305401 |
7 | 2254354560643 |
oct | 367465653151 |
9 | 104701668611 |
10 | 33233000041 |
11 | 1310418689a |
12 | 65357b8261 |
13 | 3198119287 |
14 | 1873983893 |
15 | ce7894c61 |
hex | 7bcd75669 |
33233000041 has 2 divisors, whose sum is σ = 33233000042. Its totient is φ = 33233000040.
The previous prime is 33233000011. The next prime is 33233000063. The reversal of 33233000041 is 14000033233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22013953641 + 11219046400 = 148371^2 + 105920^2 .
It is a cyclic number.
It is not a de Polignac number, because 33233000041 - 27 = 33232999913 is a prime.
It is a super-2 number, since 2×332330000412 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33232999982 and 33233000018.
It is not a weakly prime, because it can be changed into another prime (33233000011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16616500020 + 16616500021.
It is an arithmetic number, because the mean of its divisors is an integer number (16616500021).
Almost surely, 233233000041 is an apocalyptic number.
It is an amenable number.
33233000041 is a deficient number, since it is larger than the sum of its proper divisors (1).
33233000041 is an equidigital number, since it uses as much as digits as its factorization.
33233000041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 19.
Adding to 33233000041 its reverse (14000033233), we get a palindrome (47233033274).
The spelling of 33233000041 in words is "thirty-three billion, two hundred thirty-three million, forty-one", and thus it is an aban number.
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