Base | Representation |
---|---|
bin | 110000010111110011111… |
… | …100011010101110011011 |
3 | 102202210002102011011122102 |
4 | 300113303330122232123 |
5 | 413430230204441103 |
6 | 11023023243114015 |
7 | 462105233245541 |
oct | 60276374325633 |
9 | 12683072134572 |
10 | 3324102421403 |
11 | 1071820180a05 |
12 | 45829721290b |
13 | 1b15ccc3880a |
14 | b6c5d0d5d91 |
15 | 5b702dc5e88 |
hex | 305f3f1ab9b |
3324102421403 has 2 divisors, whose sum is σ = 3324102421404. Its totient is φ = 3324102421402.
The previous prime is 3324102421307. The next prime is 3324102421417. The reversal of 3324102421403 is 3041242014233.
3324102421403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3324102421403 - 226 = 3324035312539 is a prime.
It is a super-2 number, since 2×33241024214032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3324102421433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1662051210701 + 1662051210702.
It is an arithmetic number, because the mean of its divisors is an integer number (1662051210702).
Almost surely, 23324102421403 is an apocalyptic number.
3324102421403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3324102421403 is an equidigital number, since it uses as much as digits as its factorization.
3324102421403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 3324102421403 its reverse (3041242014233), we get a palindrome (6365344435636).
The spelling of 3324102421403 in words is "three trillion, three hundred twenty-four billion, one hundred two million, four hundred twenty-one thousand, four hundred three".
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