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3324213142153 is a prime number
BaseRepresentation
bin110000010111111010100…
…010110010001010001001
3102202210101010111100221221
4300113322202302022021
5413430442031022103
611023042240202041
7462111046331551
oct60277242621211
912683333440857
103324213142153
111071877725062
12458308309321
131b1619b63c57
14b6c6dab8161
155b70c9971bd
hex305fa8b2289

3324213142153 has 2 divisors, whose sum is σ = 3324213142154. Its totient is φ = 3324213142152.

The previous prime is 3324213142087. The next prime is 3324213142157. The reversal of 3324213142153 is 3512413124233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3096009164304 + 228203977849 = 1759548^2 + 477707^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3324213142153 is a prime.

It is a super-2 number, since 2×33242131421532 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3324213142157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1662106571076 + 1662106571077.

It is an arithmetic number, because the mean of its divisors is an integer number (1662106571077).

Almost surely, 23324213142153 is an apocalyptic number.

It is an amenable number.

3324213142153 is a deficient number, since it is larger than the sum of its proper divisors (1).

3324213142153 is an equidigital number, since it uses as much as digits as its factorization.

3324213142153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 51840, while the sum is 34.

Adding to 3324213142153 its reverse (3512413124233), we get a palindrome (6836626266386).

The spelling of 3324213142153 in words is "three trillion, three hundred twenty-four billion, two hundred thirteen million, one hundred forty-two thousand, one hundred fifty-three".