Base | Representation |
---|---|
bin | 110000011000000001100… |
… | …100110011101001001010 |
3 | 102202210200100110220120211 |
4 | 300120001210303221022 |
5 | 413431212231104114 |
6 | 11023102052511334 |
7 | 462114011142151 |
oct | 60300144635112 |
9 | 12683610426524 |
10 | 3324331113034 |
11 | 1071928280358 |
12 | 45833b91b54a |
13 | 1b163842a3c9 |
14 | b6c81626598 |
15 | 5b717eeb6c4 |
hex | 30601933a4a |
3324331113034 has 64 divisors (see below), whose sum is σ = 5490989274240. Its totient is φ = 1502418677760.
The previous prime is 3324331113023. The next prime is 3324331113071. The reversal of 3324331113034 is 4303111334233.
It is a super-2 number, since 2×33243311130342 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3324331112987 and 3324331113005.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 144568642 + ... + 144591634.
It is an arithmetic number, because the mean of its divisors is an integer number (85796707410).
Almost surely, 23324331113034 is an apocalyptic number.
3324331113034 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
3324331113034 is a deficient number, since it is larger than the sum of its proper divisors (2166658161206).
3324331113034 is a wasteful number, since it uses less digits than its factorization.
3324331113034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23815.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 3324331113034 its reverse (4303111334233), we get a palindrome (7627442447267).
The spelling of 3324331113034 in words is "three trillion, three hundred twenty-four billion, three hundred thirty-one million, one hundred thirteen thousand, thirty-four".
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