33254000113 has 4 divisors (see below), whose sum is σ = 33254760448. Its totient is φ = 33253239780.

The previous prime is 33254000063. The next prime is 33254000119. The reversal of 33254000113 is 31100045233.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33254000113 is a prime.

It is a super-2 number, since 2×33254000113² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33254000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310281 + ... + 403462.

It is an arithmetic number, because the mean of its divisors is an integer number (8313690112).

Almost surely, 2^33254000113 is an apocalyptic number.

It is an amenable number.

33254000113 is a deficient number, since it is larger than the sum of its proper divisors (760335).

33254000113 is an equidigital number, since it uses as much as digits as its factorization.

33254000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760334.

The product of its (nonzero) digits is 1080, while the sum is 22.

Adding to 33254000113 its reverse (31100045233), we get a palindrome (64354045346).

The spelling of 33254000113 in words is "thirty-three billion, two hundred fifty-four million, one hundred thirteen", and thus it is an aban number.