Base | Representation |
---|---|
bin | 110000011101011010101… |
… | …011100001000001101011 |
3 | 102210100121212012012212121 |
4 | 300131122223201001223 |
5 | 414030041434330212 |
6 | 11025500402252111 |
7 | 462410334361066 |
oct | 60353253410153 |
9 | 12710555165777 |
10 | 3330121011307 |
11 | 1074329549652 |
12 | 459496957037 |
13 | 1b204bb12c0c |
14 | b72705838dd |
15 | 5b956481d07 |
hex | 3075aae106b |
3330121011307 has 2 divisors, whose sum is σ = 3330121011308. Its totient is φ = 3330121011306.
The previous prime is 3330121011229. The next prime is 3330121011353. The reversal of 3330121011307 is 7031101210333.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3330121011307 - 27 = 3330121011179 is a prime.
It is a super-3 number, since 3×33301210113073 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3330121011367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665060505653 + 1665060505654.
It is an arithmetic number, because the mean of its divisors is an integer number (1665060505654).
Almost surely, 23330121011307 is an apocalyptic number.
3330121011307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3330121011307 is an equidigital number, since it uses as much as digits as its factorization.
3330121011307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 3330121011307 in words is "three trillion, three hundred thirty billion, one hundred twenty-one million, eleven thousand, three hundred seven".
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