Base | Representation |
---|---|
bin | 1111001001100100100011… |
… | …01111001011100100010001 |
3 | 11100221210210200011121022212 |
4 | 13210302101233023210101 |
5 | 13331310001110142431 |
6 | 154504200515441505 |
7 | 10005605133522464 |
oct | 744622157134421 |
9 | 140853720147285 |
10 | 33314211412241 |
11 | a68452892a421 |
12 | 38a0625bb6295 |
13 | 157869412b506 |
14 | 8325b89b12db |
15 | 3cb8a467072b |
hex | 1e4c91bcb911 |
33314211412241 has 4 divisors (see below), whose sum is σ = 33314261592612. Its totient is φ = 33314161231872.
The previous prime is 33314211412199. The next prime is 33314211412309. The reversal of 33314211412241 is 14221411241333.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4255643052241 + 29058568360000 = 2062921^2 + 5390600^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33314211412241 is a prime.
It is a super-2 number, since 2×333142114122412 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 33314211412198 and 33314211412207.
It is not an unprimeable number, because it can be changed into a prime (33314211462241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24080816 + ... + 25426641.
It is an arithmetic number, because the mean of its divisors is an integer number (8328565398153).
Almost surely, 233314211412241 is an apocalyptic number.
It is an amenable number.
33314211412241 is a deficient number, since it is larger than the sum of its proper divisors (50180371).
33314211412241 is an equidigital number, since it uses as much as digits as its factorization.
33314211412241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50180370.
The product of its digits is 13824, while the sum is 32.
Adding to 33314211412241 its reverse (14221411241333), we get a palindrome (47535622653574).
The spelling of 33314211412241 in words is "thirty-three trillion, three hundred fourteen billion, two hundred eleven million, four hundred twelve thousand, two hundred forty-one".
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