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333142424401 = 1583210450047
BaseRepresentation
bin1001101100100001101…
…01011111101101010001
31011211220021020122000011
410312100311133231101
520424233430040101
6413013222154521
733032402612353
oct4662065375521
91154807218004
10333142424401
11119315239296
1254694882a41
1325552253c17
14121a4a690d3
1589ec111751
hex4d90d5fb51

333142424401 has 4 divisors (see below), whose sum is σ = 333352876032. Its totient is φ = 332931972772.

The previous prime is 333142424399. The next prime is 333142424441. The reversal of 333142424401 is 104424241333.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 333142424401 - 21 = 333142424399 is a prime.

It is a super-2 number, since 2×3331424244012 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (333142424441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105223441 + ... + 105226606.

It is an arithmetic number, because the mean of its divisors is an integer number (83338219008).

Almost surely, 2333142424401 is an apocalyptic number.

It is an amenable number.

333142424401 is a deficient number, since it is larger than the sum of its proper divisors (210451631).

333142424401 is a wasteful number, since it uses less digits than its factorization.

333142424401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210451630.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 333142424401 its reverse (104424241333), we get a palindrome (437566665734).

The spelling of 333142424401 in words is "three hundred thirty-three billion, one hundred forty-two million, four hundred twenty-four thousand, four hundred one".

Divisors: 1 1583 210450047 333142424401