33320234131 has 4 divisors (see below), whose sum is σ = 33367767264. Its totient is φ = 33272701000.

The previous prime is 33320234119. The next prime is 33320234147. The reversal of 33320234131 is 13143202333.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 33320234131 - 2¹⁵ = 33320201363 is a prime.

It is a super-2 number, since 2×33320234131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33320234096 and 33320234105.

It is not an unprimeable number, because it can be changed into a prime (33320234111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23765515 + ... + 23766916.

It is an arithmetic number, because the mean of its divisors is an integer number (8341941816).

Almost surely, 2^33320234131 is an apocalyptic number.

33320234131 is a deficient number, since it is larger than the sum of its proper divisors (47533133).

33320234131 is an equidigital number, since it uses as much as digits as its factorization.

33320234131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47533132.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 33320234131 its reverse (13143202333), we get a palindrome (46463436464).

The spelling of 33320234131 in words is "thirty-three billion, three hundred twenty million, two hundred thirty-four thousand, one hundred thirty-one".