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3332112302041 is a prime number
BaseRepresentation
bin110000011111010001010…
…111101011111111011001
3102210112202122011021020021
4300133101113223333121
5414043131222131131
611030430134430441
7462510564150325
oct60372127537731
912715678137207
103332112302041
111075160587876
12459951802421
131b22a852b063
14b73bcc12985
155ba211c3e11
hex307d15ebfd9

3332112302041 has 2 divisors, whose sum is σ = 3332112302042. Its totient is φ = 3332112302040.

The previous prime is 3332112302033. The next prime is 3332112302047. The reversal of 3332112302041 is 1402032112333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1698838526025 + 1633273776016 = 1303395^2 + 1277996^2 .

It is a cyclic number.

It is not a de Polignac number, because 3332112302041 - 23 = 3332112302033 is a prime.

It is a super-2 number, since 2×33321123020412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3332112301997 and 3332112302015.

It is not a weakly prime, because it can be changed into another prime (3332112302047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1666056151020 + 1666056151021.

It is an arithmetic number, because the mean of its divisors is an integer number (1666056151021).

Almost surely, 23332112302041 is an apocalyptic number.

It is an amenable number.

3332112302041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3332112302041 is an equidigital number, since it uses as much as digits as its factorization.

3332112302041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3332112302041 its reverse (1402032112333), we get a palindrome (4734144414374).

The spelling of 3332112302041 in words is "three trillion, three hundred thirty-two billion, one hundred twelve million, three hundred two thousand, forty-one".