Base | Representation |
---|---|
bin | 1100011010100010… |
… | …1100000111101001 |
3 | 22121020210100100220 |
4 | 3012220230013221 |
5 | 23311113231431 |
6 | 1310404120253 |
7 | 145404152331 |
oct | 30650540751 |
9 | 8536710326 |
10 | 3332555241 |
11 | 1460160094 |
12 | 790096089 |
13 | 4115703a2 |
14 | 2388520c1 |
15 | 147883b96 |
hex | c6a2c1e9 |
3332555241 has 4 divisors (see below), whose sum is σ = 4443406992. Its totient is φ = 2221703492.
The previous prime is 3332555221. The next prime is 3332555269. The reversal of 3332555241 is 1425552333.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3332555241 is a prime.
It is a super-3 number, since 3×33325552413 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3332555221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555425871 + ... + 555425876.
It is an arithmetic number, because the mean of its divisors is an integer number (1110851748).
Almost surely, 23332555241 is an apocalyptic number.
It is an amenable number.
3332555241 is a deficient number, since it is larger than the sum of its proper divisors (1110851751).
3332555241 is a wasteful number, since it uses less digits than its factorization.
3332555241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1110851750.
The product of its digits is 54000, while the sum is 33.
The square root of 3332555241 is about 57728.2880484083. The cubic root of 3332555241 is about 1493.6853415848.
The spelling of 3332555241 in words is "three billion, three hundred thirty-two million, five hundred fifty-five thousand, two hundred forty-one".
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