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33330012113 = 83401566411
BaseRepresentation
bin11111000010100111…
…111001111111010001
310012000211022001020002
4133002213321333101
51021224440341423
623151145455345
72256643266656
oct370247717721
9105024261202
1033330012113
1113153a17462
1265621a1555
1331b2254a78
1418827d7c2d
15d01159228
hex7c29f9fd1

33330012113 has 4 divisors (see below), whose sum is σ = 33731578608. Its totient is φ = 32928445620.

The previous prime is 33330012083. The next prime is 33330012119. The reversal of 33330012113 is 31121003333.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 33330012113 - 210 = 33330011089 is a prime.

It is a super-2 number, since 2×333300121132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33330012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200783123 + ... + 200783288.

It is an arithmetic number, because the mean of its divisors is an integer number (8432894652).

Almost surely, 233330012113 is an apocalyptic number.

It is an amenable number.

33330012113 is a deficient number, since it is larger than the sum of its proper divisors (401566495).

33330012113 is an equidigital number, since it uses as much as digits as its factorization.

33330012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 401566494.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 33330012113 its reverse (31121003333), we get a palindrome (64451015446).

The spelling of 33330012113 in words is "thirty-three billion, three hundred thirty million, twelve thousand, one hundred thirteen".

Divisors: 1 83 401566411 33330012113