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33332040121 = 473989177787
BaseRepresentation
bin11111000010101111…
…101001000110111001
310012000222010002010111
4133002233221012321
51021231000240441
623151301144321
72256666444352
oct370257510671
9105028102114
1033332040121
11131550820a6
1265629bb0a1
1331b27b4b83
141882ba4d29
15d0140a081
hex7c2be91b9

33332040121 has 8 divisors (see below), whose sum is σ = 34049957760. Its totient is φ = 32614486128.

The previous prime is 33332040073. The next prime is 33332040127. The reversal of 33332040121 is 12104023333.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 33332040121 - 211 = 33332038073 is a prime.

It is a super-2 number, since 2×333320401212 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33332040092 and 33332040101.

It is not an unprimeable number, because it can be changed into a prime (33332040127) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98590 + ... + 276376.

It is an arithmetic number, because the mean of its divisors is an integer number (4256244720).

Almost surely, 233332040121 is an apocalyptic number.

It is an amenable number.

33332040121 is a deficient number, since it is larger than the sum of its proper divisors (717917639).

33332040121 is a wasteful number, since it uses less digits than its factorization.

33332040121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181823.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 33332040121 its reverse (12104023333), we get a palindrome (45436063454).

The spelling of 33332040121 in words is "thirty-three billion, three hundred thirty-two million, forty thousand, one hundred twenty-one".

Divisors: 1 47 3989 177787 187483 8355989 709192343 33332040121