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33343142104457 is a prime number
BaseRepresentation
bin1111001010011010011100…
…01001000000110110001001
311101001120110220101001011222
413211031032021000312021
513332243223334320312
6154525343352531425
710010651100406103
oct745151611006611
9141046426331158
1033343142104457
11a695824511709
1238a615a9b0b75
13157b324aca9c3
14833b60dca573
153cc4e9477672
hex1e534e240d89

33343142104457 has 2 divisors, whose sum is σ = 33343142104458. Its totient is φ = 33343142104456.

The previous prime is 33343142104427. The next prime is 33343142104469. The reversal of 33343142104457 is 75440124134333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31942176331081 + 1400965773376 = 5651741^2 + 1183624^2 .

It is a cyclic number.

It is not a de Polignac number, because 33343142104457 - 214 = 33343142088073 is a prime.

It is a super-2 number, since 2×333431421044572 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (33343142104427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16671571052228 + 16671571052229.

It is an arithmetic number, because the mean of its divisors is an integer number (16671571052229).

Almost surely, 233343142104457 is an apocalyptic number.

It is an amenable number.

33343142104457 is a deficient number, since it is larger than the sum of its proper divisors (1).

33343142104457 is an equidigital number, since it uses as much as digits as its factorization.

33343142104457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 44.

The spelling of 33343142104457 in words is "thirty-three trillion, three hundred forty-three billion, one hundred forty-two million, one hundred four thousand, four hundred fifty-seven".