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33345345051 = 327907468577
BaseRepresentation
bin11111000011100010…
…011001011000011011
310012001220011001001200
4133003202121120123
51021242402020201
623152454245243
72260220520264
oct370342313033
9105056131050
1033345345051
111316163a307
126567356823
1331b5492b05
14188486996b
15d02687386
hex7c389961b

33345345051 has 12 divisors (see below), whose sum is σ = 48171692712. Its totient is φ = 22227371136.

The previous prime is 33345345041. The next prime is 33345345101. The reversal of 33345345051 is 15054354333.

It is not a de Polignac number, because 33345345051 - 210 = 33345344027 is a prime.

It is a super-2 number, since 2×333453450512 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33345344997 and 33345345015.

It is not an unprimeable number, because it can be changed into a prime (33345345041) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 163126 + ... + 305451.

It is an arithmetic number, because the mean of its divisors is an integer number (4014307726).

Almost surely, 233345345051 is an apocalyptic number.

33345345051 is a deficient number, since it is larger than the sum of its proper divisors (14826347661).

33345345051 is a wasteful number, since it uses less digits than its factorization.

33345345051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 476490 (or 476487 counting only the distinct ones).

The product of its (nonzero) digits is 162000, while the sum is 36.

Adding to 33345345051 its reverse (15054354333), we get a palindrome (48399699384).

The spelling of 33345345051 in words is "thirty-three billion, three hundred forty-five million, three hundred forty-five thousand, fifty-one".

Divisors: 1 3 9 7907 23721 71163 468577 1405731 4217193 3705038339 11115115017 33345345051