Base | Representation |
---|---|
bin | 110000100110101110110… |
… | …000000011110110001010 |
3 | 102211022102210201210001211 |
4 | 300212232300003312022 |
5 | 414211032041020432 |
6 | 11034233002003334 |
7 | 463213215440032 |
oct | 60465660036612 |
9 | 12738383653054 |
10 | 3340121423242 |
11 | 10785a05150aa |
12 | 45b407aa654a |
13 | 1b2c83915a26 |
14 | b793c7b28c2 |
15 | 5bd3e3c1d47 |
hex | 309aec03d8a |
3340121423242 has 4 divisors (see below), whose sum is σ = 5010182134866. Its totient is φ = 1670060711620.
The previous prime is 3340121423213. The next prime is 3340121423273. The reversal of 3340121423242 is 2423241210433.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2383537664641 + 956583758601 = 1543871^2 + 978051^2 .
It is a super-2 number, since 2×33401214232422 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 835030355809 + ... + 835030355812.
Almost surely, 23340121423242 is an apocalyptic number.
3340121423242 is a deficient number, since it is larger than the sum of its proper divisors (1670060711624).
3340121423242 is a wasteful number, since it uses less digits than its factorization.
3340121423242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1670060711623.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 3340121423242 its reverse (2423241210433), we get a palindrome (5763362633675).
The spelling of 3340121423242 in words is "three trillion, three hundred forty billion, one hundred twenty-one million, four hundred twenty-three thousand, two hundred forty-two".
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