Base | Representation |
---|---|
bin | 110000100110101110111… |
… | …101110111001001100011 |
3 | 102211022110001112121001011 |
4 | 300212232331313021203 |
5 | 414211034002310001 |
6 | 11034233211321351 |
7 | 463213261256125 |
oct | 60465675671143 |
9 | 12738401477034 |
10 | 3340125041251 |
11 | 10785a2566399 |
12 | 45b409150257 |
13 | 1b2c845b176b |
14 | b793d075215 |
15 | 5bd3e888d51 |
hex | 309aef77263 |
3340125041251 has 16 divisors (see below), whose sum is σ = 3555437580288. Its totient is φ = 3126908188800.
The previous prime is 3340125041249. The next prime is 3340125041293. The reversal of 3340125041251 is 1521405210433.
It is a cyclic number.
It is not a de Polignac number, because 3340125041251 - 21 = 3340125041249 is a prime.
It is a super-2 number, since 2×33401250412512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3340125041221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42181186 + ... + 42260296.
It is an arithmetic number, because the mean of its divisors is an integer number (222214848768).
Almost surely, 23340125041251 is an apocalyptic number.
3340125041251 is a deficient number, since it is larger than the sum of its proper divisors (215312539037).
3340125041251 is a wasteful number, since it uses less digits than its factorization.
3340125041251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92322.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 3340125041251 in words is "three trillion, three hundred forty billion, one hundred twenty-five million, forty-one thousand, two hundred fifty-one".
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