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33404130020434 = 233150459410907
BaseRepresentation
bin1111001100001100000010…
…10011011100110001010010
311101021101220020220011212211
413212012001103130301102
513334243124241123214
6155013351231342334
710015240324215235
oct746060123346122
9141241806804784
1033404130020434
11a709680609658
1238b5b3b6819aa
131583cc4123a54
14836aa8b6341c
153cddb87c10c4
hex1e61814dcc52

33404130020434 has 8 divisors (see below), whose sum is σ = 50257573264368. Its totient is φ = 16651605598980.

The previous prime is 33404130020413. The next prime is 33404130020507. The reversal of 33404130020434 is 43402003140433.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×334041300204342 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33404130020396 and 33404130020405.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25229704792 + ... + 25229706115.

It is an arithmetic number, because the mean of its divisors is an integer number (6282196658046).

Almost surely, 233404130020434 is an apocalyptic number.

33404130020434 is a deficient number, since it is larger than the sum of its proper divisors (16853443243934).

33404130020434 is a wasteful number, since it uses less digits than its factorization.

33404130020434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50459411240.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 33404130020434 its reverse (43402003140433), we get a palindrome (76806133160867).

The spelling of 33404130020434 in words is "thirty-three trillion, four hundred four billion, one hundred thirty million, twenty thousand, four hundred thirty-four".

Divisors: 1 2 331 662 50459410907 100918821814 16702065010217 33404130020434