3340443300001 has 4 divisors (see below), whose sum is σ = 3418128027952. Its totient is φ = 3262758572052.

The previous prime is 3340443299983. The next prime is 3340443300013. The reversal of 3340443300001 is 1000033440433.

3340443300001 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3340443300001 - 2¹⁵ = 3340443267233 is a prime.

It is a super-2 number, since 2×3340443300001² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3340443300031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38842363911 + ... + 38842363996.

It is an arithmetic number, because the mean of its divisors is an integer number (854532006988).

Almost surely, 2^{3340443300001} is an apocalyptic number.

It is an amenable number.

3340443300001 is a deficient number, since it is larger than the sum of its proper divisors (77684727951).

3340443300001 is an equidigital number, since it uses as much as digits as its factorization.

3340443300001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77684727950.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 3340443300001 its reverse (1000033440433), we get a palindrome (4340476740434).

The spelling of 3340443300001 in words is "three trillion, three hundred forty billion, four hundred forty-three million, three hundred thousand, one".