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334111214114 = 2167055607057
BaseRepresentation
bin1001101110010101001…
…01001000101000100010
31011221101210012020122122
410313022211020220202
520433224432322424
6413253310504242
733065405314226
oct4671245105042
91157353166578
10334111214114
11119772085347
1254905205082
1325677b84282
14122575b0786
158a571ca45e
hex4dca948a22

334111214114 has 4 divisors (see below), whose sum is σ = 501166821174. Its totient is φ = 167055607056.

The previous prime is 334111214083. The next prime is 334111214147. The reversal of 334111214114 is 411412111433.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411412111433 = 1417612902153.

It can be written as a sum of positive squares in only one way, i.e., 194231474089 + 139879740025 = 440717^2 + 374005^2 .

It is a super-2 number, since 2×3341112141142 (a number of 24 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83527803527 + ... + 83527803530.

Almost surely, 2334111214114 is an apocalyptic number.

334111214114 is a deficient number, since it is larger than the sum of its proper divisors (167055607060).

334111214114 is a wasteful number, since it uses less digits than its factorization.

334111214114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167055607059.

The product of its digits is 1152, while the sum is 26.

Adding to 334111214114 its reverse (411412111433), we get a palindrome (745523325547).

The spelling of 334111214114 in words is "three hundred thirty-four billion, one hundred eleven million, two hundred fourteen thousand, one hundred fourteen".

Divisors: 1 2 167055607057 334111214114